LeetCode - 56.Merge Intervals
Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18]
,
return [1,6],[8,10],[15,18]
.
Solution
/**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
public:
vector<Interval> merge(vector<Interval>& intervals) {
std::sort(
intervals.begin(),
intervals.end(),
[](const Interval& a, const Interval& b) {
return a.start < b.start;
});
auto it = intervals.begin();
while(it != intervals.end() && (it + 1) != intervals.end()) {
if (merge(*it, *it, *(it + 1))) {
intervals.erase(it + 1);
} else {
it++;
}
}
return intervals;
}
bool merge(Interval& out, const Interval& one, const Interval& another) {
if (one.start > another.end || another.start > one.end) {
return false;
}
out.start = std::min(one.start, another.start);
out.end = std::max(one.end, another.end);
return true;
}
};